Using a trigonometric solution, find the magnitude and direction of the resultant vector from the following
forces 6.5m/s at 45°, 9m/s at 180°, 14km/hr at 205°, and 8.7m/s at 305° The vector directions are referenced to a co-ordinate system where 0° represents the right horizontal and positive angles are in a counterclockwise direction.
how to solve properly?
when drawing out the horizontal and vertical lines if it points left or down do you let your final answer be negative?
The Attempt at a Solution
i converted 14 km/hr into m/s which is 3.88
i got all my vertical and horizontal numbers and added them up. did the Pythagorean theorem but my answer is off. so I was wondering if it how my triangles were drawn. i.e my 305 degree triangle had horizontal moving left and vertical moving up, leaving my final vertical number to be positive and horizontal to be negative? correct.