 Problem Statement
 When f(x) is divided by (x^2 + 4) the remainder is (2x + 1) and when f(x) is divided by (x^2 + 6) the remainder is (6x  1). Given that the remainder of f(x) when divided by (x^4 + 10x^2 + 24) is r(x), find the value of r(4)
 Relevant Equations

f(x) = divisor * quotient + remainder
remainder theorem
f(x) = A(x) . (x^{2} + 4) + 2x + 1
f(x) = B(x). (x^{2} + 6) + 6x  1
f(x) = C(x) . (x^{2} + 6) . (x^{2} + 4) + s(x)
Then I am stuck. What will be the next step?
Thanks
f(x) = B(x). (x^{2} + 6) + 6x  1
f(x) = C(x) . (x^{2} + 6) . (x^{2} + 4) + s(x)
Then I am stuck. What will be the next step?
Thanks