p^2=P^2+2pq+q^2Originally posted by Hyperreality
This is what I've done afterwards, but I'm not sure if it is right.
Let p^2 = x^2 + 2xy + y^2.
where y^2 = y.y or -y.-y or x^2 = x.x or -x.-x.
When y = -x, or x = -y, p^2 = 0
Therefore (x + y) is a factor of p^2, also (x + y) = (p + q)
Therefore p^2 = p^2 + 2pq + p^2. p^2 = 0 when p = -q,
but (p)^2 = (-q)^2
p^2 = q^2
therefore (p+q)mod q^2 = 0
Are there any flaw in my argument or have I made any calcuation error?