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Remembered Test Question?

  1. Apr 5, 2006 #1
    I just took a test in Pre-Algerbra. I remember a question that went like this.

    "The sum of two numbers is 8"
    "The sum of these numbers squared is 40"
    "What are the numbers?"

    Is the inital equation that I came up with right/wrong?

    [tex](x^2+y^2)+(x+y)=(40+8)[\tex]
     
    Last edited: Apr 5, 2006
  2. jcsd
  3. Apr 5, 2006 #2
    OK.........my latex is not working
    WHY
     
  4. Apr 5, 2006 #3

    Hurkyl

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    You used the wrong slash. You wanted /

    And while what you wrote is correct (assuming x and y denote your two numbers), I wonder why you wrote two assertions as one equation.
     
  5. Apr 5, 2006 #4
    "The sum of two numbers is 8"
    "The sum of these numbers squared is 40"
    "What are the numbers?"

    Is the inital equation that I came up with right/wrong?

    [tex](x^2+y^2)+(x+y)=(40+8)[/tex]


    OK....I don't know why I did this. I'm afraid I do this too often.
     
  6. Apr 5, 2006 #5
    "I wonder why you wrote two assertions as one equation."

    what does this mean?
     
  7. Apr 5, 2006 #6

    Hurkyl

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    In the problem, there were two statements:

    "The sum of two numbers is 8"
    "The sum of these numbers squared is 40"

    So it seems odd that your mathematical model only has one statement:

    [tex](x^2+y^2)+(x+y)=(40+8)[/tex]
     
  8. Apr 5, 2006 #7
    are you refering to that this can also be written like-

    [tex](x^2+y^2)+x+y=48[/tex] ?
     
  9. Apr 5, 2006 #8
    No he means that there are two seperate statements and you have no reason to combine them, so why are you?
     
  10. Apr 5, 2006 #9
    Ok...........like most of the other students in my class............I have know idea of what you are talking about. Are you saying to write it like this-

    [tex](x+y)^2+x+y=48[/tex]

    my major problem in understanding this is understanding the terminology.
     
  11. Apr 5, 2006 #10
    "No he means that there are two seperate statements and you have no reason to combine them, so why are you?"

    If they have the same variables...........how can you not?
     
  12. Apr 5, 2006 #11
    Are you saying-

    [tex](x+y)^2+x+y=48 ?[/tex]
     
    Last edited: Apr 5, 2006
  13. Apr 5, 2006 #12
    Is there a differnce if I write it like-

    [tex](x^2+y^2)+x+y=48[/tex]
     
  14. Apr 5, 2006 #13
    did I say something wrong?
     
  15. Apr 5, 2006 #14

    Hurkyl

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    Very easily: by not doing it.


    x² + y² is certainly different than (x + y)². (But that has nothing to do with what we're saying)
     
  16. Apr 5, 2006 #15
    Too many ridles...............I have been at this for 4 days.
    Are you saying that there are 4 different variables?
     
  17. Apr 5, 2006 #16

    Hurkyl

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    I think you have the variables right: one variable for each of the numbers you're looking for.

    But the problem made two statements about them. So, you should have two equations!
     
  18. Apr 5, 2006 #17
    OH...........X is the answer to the first statment, and Y is the answer to the second?
     
  19. Apr 5, 2006 #18

    Hurkyl

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    The first step is not to answer the question. The first step is to translate the question into a mathematical problem.
     
  20. Apr 5, 2006 #19
    [tex]x+x=8[/tex]
    and
    [tex]y^2+y^2=40[/tex]
     
  21. Apr 5, 2006 #20
    OK.....how about this-

    [tex]x+y=8[/tex]
    and
    [tex]x^2+y^2=40[/tex]
     
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