1. The problem statement, all variables and given/known data In a container we have a gas, at P = 11.0 atm & T = 20.0 C. We remove 2/3rds of the gas and increase the temperature to T = 75.0 C.What's the pressure of the gas that remains? 2. Relevant equations PV = nRT 3. The attempt at a solution Normally this would be a regular "put the numbers in the formula" exercise, but I'm having trouble understanding just what "remove 2/3rds of the gas" means. If the gas was, say, a block of wood, I'd be removing 2/3ds of its mass. With that logic, I figured it was the n (moles) that were decreased, and that the volume V was kept the same (same container). But I didn't get the wanted result from this, so I was wrong. Then I figured maybe the change happens so fast that the gas doesn't manage to spread and have the same Volume again, so both n & V should be n' = n/3 & V' = V/3. That didn't work either. So I'm kinda stuck on what that phrase means. Any help is appreciated!