Ohm's Law, Equations for parallel and series combinations of resistors[/B]
The Attempt at a Solution
Working this problem I obtain a solution that doesn't make sense, which is that the bulbs are dimmer.
If I assign 10 ohms to each bulb, I believe the total resistance would be:
After removing A, it would just be 30 ohms.
Before: 25 ohms
After: 30 ohms
So now there's more resistance and less current? [/B]