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Replace the system of two forces and once couple by a Wrench

  1. Oct 4, 2012 #1
    *The title for this question is incorrect. I messed it up with another question. My apologies.

    1. The problem statement, all variables and given/known data

    Replace the system of two forces and one couple shown in Prob. 2/158 by a wrench. Determine the magnitude of the moment M of the wrench, the magnitude of the force R of the wrench, and the coordinates of the point P in the x-y plane through which the wrench passes.


    2. Relevant equations



    3. The attempt at a solution
    I found the magnitude of the resultant to be:

    Rx = -49 kN
    Ry = -35*sin(69.04) = -32.684
    Rz = 35*cos(69.04)

    R = 60.216 kN

    I'm fairly sure that this value is correct but I am not sure

    Then for the moment I got:

    Mx = -35*cos(20.956)*1.8m + 35sin(20.956)(4.7m) = 0
    My = 49*1.8m = 88.2 kNm
    Mz -36 kNm

    M = 95.264 kNm

    But it says this answer is wrong.

    From this point I am unsure how to find the location of the x and y coordinate

    All help would be appreciated
     

    Attached Files:

    Last edited: Oct 4, 2012
  2. jcsd
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