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Representation of lorentz group

  1. Jan 8, 2009 #1
    1. The problem statement, all variables and given/known data
    i) Show that the Lorentz group has representations on any space [tex]\mathbb{R}^d[/tex]
    any d = 4n with n = 0, 1, 2, . . .. Show that those with n > 1 are not
    irreducible. (Hint: here it might be useful to work with tensors in index
    notation and to think of symmetry properties.)

    2. Relevant equations

    3. The attempt at a solution
    I have no idea where to begin, i do however know how to show that they are not irreducible.
    I mean if this was R^4 tensor itself n times than i could form rank (n,0) tensors, but this is R^4^n, which has vectors as elements, with 4^n components. Please help
  2. jcsd
  3. Jan 9, 2009 #2
  4. Jan 11, 2009 #3
    Come on ppl someone must know!
  5. Jan 11, 2009 #4
    Seriously, this problem is by no means trivial and you just have to crank it out or consult some Lie groups book.

    Look at the lie algebra structure (tangent space at identity) first and then you can exponentiate the lie algebra representation. The irreducible representations are actions on spinors. You should be able to find those info in standard QFT books.
  6. Jan 11, 2009 #5
    It cannot be this long, because this question is part of question from a past exam paper. Either there is a mistake in the question and the R^d should actually mean
    d times(in which case the question is ok) or there are reps of the lorentz group on eg R^16 which i do not know about.
  7. Jan 11, 2009 #6
    if it's from past exam paper, the professor probably expects you to know the results and derivations already.

    Like I said, the answer is actions on spinors, given by

    where [itex]S^{\mu\nu}=[J^\mu, J^\nu][/itex] are the spin operators (I might be missing a factor of 2 or i). The derivations are very nontrivial but the results are standard. You can start by looking at the lie algebra of the lorentz group. You'll get 3 spin operators and 3 boost operators. You take linearly combinations and find out that the lie algebra separates. The representation for the lie algebra is then a direction sum of two spin. You can then exponentiate this lie algebra to get the corresponding lie group.

    There is no way I can derive all these without seeing how they were done first. I suggest you consult some textbooks. Srednicki's book on QFT has a good chapter on this matter and Peskin's QFT has a guided multi-part problem that leads you to this result.
    Last edited: Jan 11, 2009
  8. Jan 11, 2009 #7


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    Has everyone forgotten about trivial actions and direct sums?
  9. Jan 11, 2009 #8
    Oh, wait, I think I might have misread your problem. I thought the problem asks for finding all representations of the Lorentz group. I apologize.

    Instead, it asks for showing that for real representations of d=4n, the representation is reducible. I can't think of a good strategy right away. I believe you need to work through the commutation relations of Lie algebra and make some clever observations.
  10. Jan 12, 2009 #9
    Ah yes! I will try this thanks.
  11. Jan 12, 2009 #10
    Woops i made a mistake! d=4^n not d=4n. So that the direct sum method of fundamental reps will not work. Instead i was thinking of this: Is, for example
    [tex]\mathbb{R}^4\otimes\mathbb{R}^4\cong\mathbb{R^{16}} ?[/tex]
    Then the tensor product of the fund (or trivial) rep with itself is also a rep of R^16 ? Is this correct?
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