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Repulsive force

  1. Feb 7, 2006 #1
    Find the repulsive force on two protons in the nucleus of an atom assuming they are separated by the minimum distance of 1.00 x 10^-15m.

    So F=k lq(1)l^2/ r^2
    =8.99 x 10^9 (1.602 x 10 ^-19)^2/(1.00 x 10^15m)

    Is this correct?
  2. jcsd
  3. Feb 8, 2006 #2


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    Answer looks right to me, though you made several mistakes in writing out the formula. :tongue2:
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