- #1
lilkrazyrae
- 64
- 0
Find the repulsive force on two protons in the nucleus of an atom assuming they are separated by the minimum distance of 1.00 x 10^-15m.
So F=k lq(1)l^2/ r^2
=8.99 x 10^9 (1.602 x 10 ^-19)^2/(1.00 x 10^15m)
=230.7N
Is this correct?
So F=k lq(1)l^2/ r^2
=8.99 x 10^9 (1.602 x 10 ^-19)^2/(1.00 x 10^15m)
=230.7N
Is this correct?