Use the method of components to find the magnitude and direction of the vector sum R1, where R1 = A + B. The vector A = 15.2 m at an angle alpha = 180 degrees from the positive horizontal axis, and vector B = 17.2 m at an angle Beta = 41.3 degrees from the positive horizontal axis.(adsbygoogle = window.adsbygoogle || []).push({});

Answer= 11.5784

So far I have answered the first three parts, but am stuck on looking for the angle of theta 2; I don't understand this part.

Part 2= What is the angle theta 1 from the positive horizontal axis of the vector sum, R1? 101.348 degrees

Part 3= What What is the magnitude of the vector difference R2 where R2 = A-B? 30.4247

The following are the parts that I don't understand.

Part 4= What is the angle theta 2 of the resulting vector?

Part 5= What is thet magnitude of the vector difference R3 where R 3 = B - A? Answer= 30.4247

Part 6= What is the angle theta 3 of the resulting vector?

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# Require Much Needed Help.

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