Hello,(adsbygoogle = window.adsbygoogle || []).push({});

I hope you don't mind this elementary question, but I got stuck with

it this evening:

GSW state in their equ. (2.1.44) that a combined reparametrisation and

a Weyl scaling obeying

d^aA^b + d^bA^a = Gamma n^ab

don't change the choosen gauge h^ab=n^ab. Now I tried to proof this.

The metric varies according to

delta n^ab = Gamma n^ab

and this should be zero. As n^ab is definitly not zero, Gamma = 0.

Then d^aA^b = - d^bA^a, which automatically implies eq. (2.1.19) to

vanish too. But then, in the coordinates sigma^+ and sigma^-,

d/d^sigma^+ A^+ = 0 = d/d^sigma^- A^-

Thus the statement that A^+=A^+(sigma^+) and similarily for A^- is

wrong, though I know is it right from other sources. So what is wrong

with my line of reasoning?

Hope someone can find some time and help me.

René.

--

René Meyer

Student of Physics & Mathematics

Zhejiang University, Hangzhou, China

**Physics Forums - The Fusion of Science and Community**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Residual conformal symmetry in GSW

Loading...

Similar Threads - Residual conformal symmetry | Date |
---|---|

A Conformal gauge theory | Aug 9, 2016 |

Conformal gravity vs loop quantum gravity | Jun 13, 2015 |

Phlip Mannheim's conformal theory of everything | Jun 6, 2015 |

Could gravity be residual strong force? | Sep 3, 2009 |

Gauge fixing and residual symmetries | Jan 28, 2008 |

**Physics Forums - The Fusion of Science and Community**