Hi. I'm trying to find the residue of(adsbygoogle = window.adsbygoogle || []).push({});

[tex]\exp{\frac{1}{z}}[/tex]

at z=0 since it is a pole, so I can integrate the function over the unit circle counterclockwise. I expanded this function in Laurent Series to get

[tex]\exp{\frac{1}{z}} = 1 + \frac{1}{1!z} + \frac{1}{2!z^2}+ ...[/tex]

So in this case the residue is the coefficient of 1/z which is 1. Is this method correct? There is no answer to it in the book...

EDIT: If you guys can find the residue using another method, please teach me.

EDIT 2: Fixed the typo :p

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# Residue of a function

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