Residue of a series.

1. Apr 23, 2017

cragar

1. The problem statement, all variables and given/known data
Use a laurent series to find the indicated residue
$f(z)=e^{\frac{-2}{z^2}}$
2. Relevant equations

3. The attempt at a solution
So I expand the series as
follows $1-\frac{2}{z^2}+\frac{2}{z^4} ...$
my book says the residue is 0 , is this because there is no residue term ?
the $a_{-1}$ term

Last edited: Apr 23, 2017
2. Apr 23, 2017

FactChecker

Yes

3. Apr 23, 2017

cragar

ok just wanted to make sure