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**1.What is the emf of a battery with a 0.15-ohm internal resistance if the battery delivers 1.5 A to an externally connected 5.0-ohm resistor?**

**Given that r = 0.15 ohm , I = 1.5 ohm , R = 5 ohm.**

By Ohm’s law V = I ( R + r)

= 1.5 (5.15)

E=7.725 V

By Ohm’s law V = I ( R + r)

= 1.5 (5.15)

E=7.725 V

Is my work/answer correct?