- #1

sonrie

- 35

- 0

What is the resistance ?

R = ____ ohms

What is the length of a copper wire 1.53 mm in diameter having the same resistance?

L= ____ m.

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- Thread starter sonrie
- Start date

- #1

sonrie

- 35

- 0

What is the resistance ?

R = ____ ohms

What is the length of a copper wire 1.53 mm in diameter having the same resistance?

L= ____ m.

- #2

mikelepore

- 551

- 2

A formula for finding the resistance when you know the resistivity of a metal and its geometric shape.

A table that lists the resistivity values for aluminum and other metals.

- #3

myominthu

- 1

- 0

A No.10 copper wire will sofly carry up to 30 Amperesof current.If the copper wire is to be replaced by an aluminium wire and the only availiable guages of aluminium wire in stock are Nos; 8,10,12,and 14 which one would be able to carry 30 A safely? Explain how you made your choice and which data you referred to.

- #4

sonrie

- 35

- 0

- #5

sonrie

- 35

- 0

For area i did 1.11*5.30= 5.88^2 =.034, then i multiplied by pi =1.08*^2.

- #6

- 12,145

- 166

sonrie, your formula Area = pi r^2 looks odd. Do you know what the "r" stands for? What is the area of a rectangle?

p.s. also, watch those units. I am seeing m, cm, and mm all being used, so we need to be careful with that.

p.s. also, watch those units. I am seeing m, cm, and mm all being used, so we need to be careful with that.

Last edited:

- #7

sonrie

- 35

- 0

- #8

- 12,145

- 166

We have the formula:

R= p L/A

Earlier you gave values for p and L which look good. We just need the correct value for area A.

Do you know how to find the area of a rectangle? Earlier you said

This statement was wrought with errors. The area of a rectangle is a simple multiplication, and it does not involve pi.For area i did 1.11*5.30= 5.88^2 =.034, then i multiplied by pi =1.08*^2

- #9

sonrie

- 35

- 0

So then my final equation should look like

R= 2.82*10^-8 3.74/2.94 = 3.59*10^-7 Is that what you got?

- #10

- 12,145

- 166

My apologies if I am mistaken. Good bye.

- #11

astrorob

- 140

- 0

Hmm, I don't think you can jump to that conclusion..

- #12

- 12,145

- 166

Hmm, I don't think you can jump to that conclusion..

Here is the evidence. These are all things sonrie has claimed in this thread:

1. The area of a rectangular cross section is given by the formula Area = pi r^2

2. In the above formula, the "r" is resistance.

3. 1.11*5.30= 5.88^2 =.034

4. The area of a rectangle is given by 0.5 B H

People can draw their own conclusions, just as I have done.

- #13

astrorob

- 140

- 0

What you may think as unimaginably easy might not be so to someone less gifted.

- #14

sonrie

- 35

- 0

So my answer is wrong!

- #15

- 12,145

- 166

He is still welcome to enlist the help of other members if he is in earnest.

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