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Resistance of a wire around the Earth
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[QUOTE="godiswatching_, post: 6569483, member: 670982"] [B]Homework Statement:[/B] Homework statement in the image. [B]Relevant Equations:[/B] $$R=\rho\frac{l}{A}$$ $$l=2\pi r$$ Hey! I had a question about this problem. I did (1) Using $$R_{0}=\rho\frac{l}{A}$$ For (2) I assume the question means that the radius increases by a meter. So I used $$\bigtriangleup L = 2\pi (r_{E}+1) - l$$ and then I used that L to find the new R. Then I said $$\bigtriangleup R = R-R_{0}$$ Does that seem right? This seems too simple to be right. My final answer was: $$\bigtriangleup R = 3.4 \cdot 10^{-4} \Omega$$ [/QUOTE]
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Resistance of a wire around the Earth
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