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Introductory Physics Homework Help
Calculating Resistance of Coaxial Cable with Isolator
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[QUOTE="bolzano95, post: 5980694, member: 638687"] [h2]Homework Statement [/h2] [SIZE=4]Coaxial cable has radius a of copper core and radius b of copper shield. Between there is an isolator with specific resistance ζ. What is the resistance of this cable with length L between the core and the shield?[/SIZE] [h2]Homework Equations[/h2] [SIZE=4]First, I tried to solve this like this: [tex]R= ζ \cdot \frac{l}{S}[/tex] In our case the length is dr, and therefore I suppose that the area of this ring is 2πrdr: [tex]dR= ζ \cdot \frac{dr}{2πrdr}[/tex][/SIZE] [h2]The Attempt at a Solution[/h2] [SIZE=4]The solution sheet says: [tex]dR= ζ \cdot \frac{dr}{2πrL}[/tex] I know that something is wrong with my equation, because dr goes away and then I cannot integrate from a to b. But why is in the solution L instead of dr? As I understand problem instruction L= b-a. And therefore L=dr which doesn't make sense to me.[/SIZE] [/QUOTE]
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Calculating Resistance of Coaxial Cable with Isolator
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