1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Resisted Motion

  1. Sep 18, 2008 #1
    1. The problem statement, all variables and given/known data

    A body of mass is projected with speed and moves under uniform gravity in a medium that exerts a resistance force of magnitude (i) mk*abs(v) or (ii) mK*(abs(v))^2 , where k and K are the positive constants and v is the velocity of the body. Gravity can be ignored. Determine the subsequent motion in each case . Verify motion the motion is bounded in case i , but not in case ii

    2. Relevant equations
    F=D+L



    3. The attempt at a solution


    for case i m*dv/dt= m*k*abs(v)

    applying seperation of variables, I get

    dv/abs(v)=kdt ==> ln(abs(v))=kt ===> v=Ce^-kt or v=Ce^kt , C being a constant and v depending on whether or not is positive or negative.

    for case two, my physical system is the quadratic resistance

    dv/dt=mk*(abs(v))^2

    applying once again the seperation of variables method I get:

    -1/K*1/v=t ==> v=-1/kt+C

    I don't understand how to verify that the body is bounded. I know that a body is bounded if it cannot overcome its gravitional potential energy. I don't understand how I can possibly ignore gravity , unless the body is completely immersed in a vacuum and that cannot be possible if a fluid force is exerting a force on the object.
     
  2. jcsd
  3. Sep 18, 2008 #2

    tiny-tim

    User Avatar
    Science Advisor
    Homework Helper

    Hi Benzoate! :smile:

    First … big mistake … resistance acceleration is negative, isn't it? :wink:

    (otherwise, your method is fine :smile:)

    As to gravity, I don't understand why they tell you that the gravity is uniform, and then tell you to ignore it! Well, ignore it anyway! :rolleyes:

    "Unbounded" means that the body goes infinitely far (in other words, x(∞) = ∞). To check that, put v = dx/dt, and integrate again to find x(∞). :smile:
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?