So, resistivity goes like [tex]\rho = R \frac{A}{l}[/tex] (where A = cross sectional area, l = length)(adsbygoogle = window.adsbygoogle || []).push({});

I solved for resistance and got [tex]R = \rho \frac{l}{A}[/tex]

If [tex]R = \rho \frac{l}{A} = \frac{V}{I}[/tex] would the current correspond to the ampacity of the material? Or, if you were to replace R in the first equation with V/I, what current value would be used in determining the resistivity of a material?

This is not a homework question. I just read about resistivity and now I'm trying to figure this out.

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Resistivity and Current

**Physics Forums | Science Articles, Homework Help, Discussion**