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Resistor ladder

  1. Jun 5, 2006 #1
    I'm not sure if I'm doing this right, I would appreciate if someone could take a look.

    Q. Find the equivalent resistance of the circuit (attached diagram). Each of the six resistors has a resistance equal to 12 ohms.

    I'm thinking that R5 and R6 are in series and therefore combine to be 2R.
    2R is now in parallel with R4, therefore 1/Req = 1/R + 1/2R = 3/2R

    Then 3/2R is in series with R2, so 2R/3 + R = 5R/3

    Then 5R/3 is in parallel with R3, so 3/5R + 1/R = 8/5R

    And since 8/5R is in series with R1, then 5R/8 + R = 13R/8.

    Have I made any major blunders??

    Attached Files:

  2. jcsd
  3. Jun 6, 2006 #2
    I get the same answer. Looks good.
  4. Jun 7, 2006 #3
    Yep, right answer .
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