Hi! A little food for thought for people who like high school physics labs.. In a standard rheostat(I have seen only the cylindrical one..the question is about rheostats of this shape..), we find a metal wire wound over a cylindrical core. The wire is wound with very closely spaced turns and as we know,it serves as a potential divider. With this sort of construction why doesn't it function as an inductor? (in any simple DC circuit with a Rh we find the current to rise to the peak instantaneously rather than exponentially as with an inductor, proving that in no way a Rh can act as an inductor).. I guess the trick lies in the construction, please apprise me of the same.. Reply please..