- #1

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Thank you in advance.

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- Thread starter BigFlorida
- Start date

- #1

- 41

- 1

Thank you in advance.

- #2

mfb

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There is no 5 ohm resistor in parallel to a 6 ohm resistor indepenent of the points you consider.

- #3

Hesch

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You could substitute the two resistors with a Thevenin-equivalent with a voltage source, Vone may say the 5 ohm resistor right after a is in parallel with the 6 ohm resistor connecting the two wires.

V

R

. . . and so on.

Use Kirchhoffs laws ( KVL and KCL ), set VIf not, how would I go about solving this?

Then calculate ( KVL and KCL ) I

R

- #4

mfb

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If they are not connected, the problem can be solved with parallel and series resistances only.

If they are connected, the posted problem statement is incomplete.

- #5

CWatters

Science Advisor

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a and b are open circuit so the 5R can be ignored.

The approach you suggested could be applicable _if_ there was a voltage source connected but you can't just add one.

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