A 3 ohm resistor is connected in parallel with a 6 ohm resistor. This pair is then connected in series with a 4 ohm resistor. These resistors are connected to a battery. What will happen if the 3 ohm resistor breaks?(adsbygoogle = window.adsbygoogle || []).push({});

I think that the power dissipated in the circuit will increase.

The other choices are that the current in the 4 ohm resistor will drop to 0, that the current in the 6 ohm resistor will increase and that the current provided by the battery will not change.

I think I am right because the 4 ohm is connected to two parallels, it will therefore not change. Is this reasonable?

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# Homework Help: Resistors in series and parallel

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