The image formed by a microscope objective with a focal length of 5 mm is 160mm from its second focal point. The eyepiece has a focal length of 26mm.
a.what is the angular magnification of the microscope?
m_o= linear magnification of objective. m_o=-L/f_o, where L is the distance from the first lens to the first image, and f_o is the focal length of the objective.
M_e=25/f_e where M_e= angular magnification of the eyepiece.
The Attempt at a Solution
So M_e=25*10/26= 9.6154, since 25 is referring to the near point in cm, I converted it to mm.
m_o= 160/5= 32
However, the correct answer is 317 so I'm about 10 off and I don't know why. I think I may be using the L term incorrectly as I don't really understand what the 160mm value is referring too. Any help would about where I went wrong above would really be appreciated.