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Resolution of Forces

  • Thread starter brandon1
  • Start date
  • #1
34
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I can't figure out how to do this one:

"Mr. Porter has attached a sign that has a weight of 495N to a wall outside his home. Determine: a) The magnitude of the tension in the chain; b) The thrust force exerted by the rod, if the angle is 35 degrees"

I'm not seeing how the answers are a) 863N and b)706.9N (my teacher gave us the answers)
 

Answers and Replies

  • #2
Päällikkö
Homework Helper
515
10
Draw a diagram.
Weight is the y-component.
 
  • #3
54
1
Can you show us what you've done so far on getting the answers?

From the answers, the rod must be at 35 degrees to the wall, rather than the horizontal. It's really only two simple calculations, just draw a diagram of forces, all there is to it.
 
  • #4
34
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What I'm not understanding is how the tension is 863N? If the signing is hanging straight down, shouldn't is be 495N [495sin(90)]?
 
Last edited:
  • #5
Päällikkö
Homework Helper
515
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It isn't hanging straight down.
 
  • #6
34
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Where do you see that?
 
  • #7
Päällikkö
Homework Helper
515
10
There's the sign, a chain, a rod and 35 degrees. I'd say the rod's placed horizontally.
 
  • #8
34
0
This is all I can get.

Physics is not exactly my best subject :redface:
 

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Last edited:
  • #10
34
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That makes a lot more sense
Thanks
 

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