(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Suppose that you wish to construct a telescope that can resolve features 7.0 km across on the Moon, 384,000 km away. You have a 2.2 m-focal-length objective lens whose diameter is 10.5 cm. What focal-length eyepiece is needed if your eye can resolve objects 0.10 mm apart at a distance of 25 cm? What is the resolution limit (radians) set by the size of the objective lens (that is, by diffraction)? Use λ=550 nm.

2. Relevant equations

Resolving power=RP=s=f*θ=(1.22*λ*f)/D where s=distance between two resolvable points, f=focal length of objective lens, D=diameter, and θ=angle between objects

3. The attempt at a solution

Using θ=(1.22*λ)/D, I got θ=6.39e-6 rad, which is correct for the second question. I don't really understand the relationship to the eyepiece in the first question though. θ=8e-3 rad for the first situation, but I'm not sure this is needed. I tried θ=s/f (even though this f refers to the objective lens) just to see what would happen and it gave f=0.125 m, which is incorrect. Any help is appreciated, thanks.

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# Homework Help: Resolution power of telescope

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