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Resonance of waves

  1. May 30, 2015 #1
    1. a source of sound is directed a large brick wall. a girl walks towards the wall and notices that the intensity of the sound decreases to aminimum every 50cm. what is the frequency of the sound? the air temperature is 20 degrees celsius (answer is 344Hz)


    2. attempted to use the universal wave equation, being V = frequency x lambda


    3. found new velocity of sound to be 343.2m/s by doing 331.4 m/s (0.59)(20degrees celsius)
    took this new velocity, and attempted to put it into the above listed equation in #2, although the equation is meant for the velocity of a WAVE, i did not know which equation to use. help please and thanks !?
     
    Last edited by a moderator: May 30, 2015
  2. jcsd
  3. May 30, 2015 #2

    NascentOxygen

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    Hi samisoccer9. Have you drawn a diagram showing the incident and reflected waves? Please attach it here.

    BTW, the title of your post would be better as INTERFERENCE OF WAVES, not RESONANCE.
     
  4. May 30, 2015 #3
    I havent drawn any diagrams consisting of waves
     
  5. May 30, 2015 #4

    haruspex

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    What do you know about reflected waves and standing waves?
     
  6. May 30, 2015 #5
    ive got the answer now , thanks tho
     
  7. May 30, 2015 #6

    berkeman

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    Can you post your solution?
     
  8. May 31, 2015 #7
    Well it says EVERY 50CM, so I took that as the distance between nodes as its a standing wave question. I assumed the brick wall to be a fixed - open, so node to node, meaning LAMBDA is equal to 2L. L being 50cm --> (2)(.5) = 1 meter.
    plug into universal wave equation v = f x lambda
    343.2 = f x lambda
    f = v/lamda --> 343.2/1
    f = 343.2 Hz
     
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