Homework Help: Resultant Force

1. Oct 19, 2013

Jud

I'm sure this problem is pretty trivial to most but apologies in advance, I'm just starting out sorry.

1. The problem statement, all variables and given/known data

I'm not sure how to go about working this out due to the 800N

3. The attempt at a solution

F1 (800N) x-pos = 800 tan (90)?? , y-pos = ???
F2 (600N) x-pos = 600 cos(30) , y-pos = -600 sin(30)
1. The problem statement, all variables and given/known data

2. Oct 19, 2013

UltrafastPED

You can draw the parallelogram of forces, and the diagonal length (from your starting point) is the net force.

Or you can complete their conversion to vectors; F1 = 800 j, where j is the unit vector in the y-direction. Your F2 looks correct ... so now add them together!

3. Oct 19, 2013

Jud

so,

F1 (800N) x-pos = 0 , y-pos = 800
F2 (600N) x-pos = 600 cos(30) , y-pos = -600 sin (30)

sqrt (519.615)^2 + (500)^2 = 721.1 N

is that correct?

4. Oct 19, 2013

UltrafastPED

It's certainly in the correct range ... if you are unsure you should recheck your calculations.

5. Oct 19, 2013

Jud

Ok Thank you for the help, greatly appreciated.