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Resultant Force

  • Thread starter Jud
  • Start date
  • #1
Jud
12
0
I'm sure this problem is pretty trivial to most but apologies in advance, I'm just starting out sorry.

Homework Statement


F2-3.jpg


I'm not sure how to go about working this out due to the 800N

The Attempt at a Solution



F1 (800N) x-pos = 800 tan (90)?? , y-pos = ???
F2 (600N) x-pos = 600 cos(30) , y-pos = -600 sin(30)

Homework Statement

 

Answers and Replies

  • #2
UltrafastPED
Science Advisor
Gold Member
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You can draw the parallelogram of forces, and the diagonal length (from your starting point) is the net force.

Or you can complete their conversion to vectors; F1 = 800 j, where j is the unit vector in the y-direction. Your F2 looks correct ... so now add them together!
 
  • #3
Jud
12
0
You can draw the parallelogram of forces, and the diagonal length (from your starting point) is the net force.

Or you can complete their conversion to vectors; F1 = 800 j, where j is the unit vector in the y-direction. Your F2 looks correct ... so now add them together!
so,

F1 (800N) x-pos = 0 , y-pos = 800
F2 (600N) x-pos = 600 cos(30) , y-pos = -600 sin (30)

sqrt (519.615)^2 + (500)^2 = 721.1 N

is that correct?
 
  • #4
UltrafastPED
Science Advisor
Gold Member
1,912
216
It's certainly in the correct range ... if you are unsure you should recheck your calculations.
 
  • #5
Jud
12
0
It's certainly in the correct range ... if you are unsure you should recheck your calculations.
Ok Thank you for the help, greatly appreciated.
 

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