- #1

Jud

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## Homework Statement

I'm not sure how to go about working this out due to the 800N

## The Attempt at a Solution

F1 (800N) x-pos = 800 tan (90)?? , y-pos = ???

F2 (600N) x-pos = 600 cos(30) , y-pos = -600 sin(30)

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- Thread starter Jud
- Start date

- #1

Jud

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I'm not sure how to go about working this out due to the 800N

F1 (800N) x-pos = 800 tan (90)?? , y-pos = ???

F2 (600N) x-pos = 600 cos(30) , y-pos = -600 sin(30)

- #2

UltrafastPED

Science Advisor

Gold Member

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Or you can complete their conversion to vectors; F1 = 800 j, where j is the unit vector in the y-direction. Your F2 looks correct ... so now add them together!

- #3

Jud

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Or you can complete their conversion to vectors; F1 = 800 j, where j is the unit vector in the y-direction. Your F2 looks correct ... so now add them together!

so,

F1 (800N) x-pos = 0 , y-pos = 800

F2 (600N) x-pos = 600 cos(30) , y-pos = -600 sin (30)

sqrt (519.615)^2 + (500)^2 = 721.1 N

is that correct?

- #4

UltrafastPED

Science Advisor

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It's certainly in the correct range ... if you are unsure you should recheck your calculations.

- #5

Jud

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It's certainly in the correct range ... if you are unsure you should recheck your calculations.

Ok Thank you for the help, greatly appreciated.

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