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Reverse Gravitational Force is the opposite force of Gravity.

It is it that keeps two bodies from not moving EXACTLY into the areas given by [itex]F=\frac {G_m_1_m_2} {r^2}[/itex]...

You can test it by using EXTREMELY precise instruments, and checking if an object on a seesaw with its more massive counterpart align exactly to form a perfectly balanced seesaw.(Of course, you put friction into the picture...duh :tongue: )

Reverse Gravity applies to both objects(in a two body system)...(By the way)

Here are the equations...they may be flawed(of course, this all may be untrue! )...

[tex]R_g_1=\frac{r^2}{Gm_1^2}[/tex]

[tex]R_g_2=\frac{r^2}{Gm_2^2}[/tex]

[tex]D_t_1=\frac{t(R_g_1)}{m}[/tex]

[tex]D_t_2=\frac{t(R_g_2)}{m}[/tex]

[tex]T_D_t_1=t(F_2-R_g_1)[/tex]

[tex]T_D_t_2=t(F_1-R_g_2)[/tex]

[tex]R_g_i_t_b=\frac{r^2}{Gm_1m_2}

Hope that's correct!(Lemme go check my notebook...)

Where F equals Gravitational Force, [itex]R_g[/itex] equals Reverse Gravitational Force(with distinctions of which body it is applying to), [itex]D_t[/itex] equals the Distance traveled because of the Reverse Gravitational force(again with distinctions), [itex]R_g_i_t_b[/itex] equals the Reverse Gravity in two bodies, [itex]T_D_t[/itex] equals the total distance traveled because of Gravity and Reverse Gravity, [itex]G[/itex] equals Newton's Gravitational Constant, [itex]m_1[/itex] equals the mass of the more massive body, and [itex]m_2[/itex] equals the mass of the less massive body.

By the way, this has been edited from its original content to fit the screen of your brain. :p

Though I did edit this.

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# Reverse Gravitational Force

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