• Support PF! Buy your school textbooks, materials and every day products Here!

Reviewing Newtonian Mechanics

  • Thread starter Bashyboy
  • Start date
  • #1
1,421
5
b]1. Homework Statement [/b]
1. Two seconds after being projected from ground level (y=0 m), a projectile is displaced
x=40 m horizontally and y=53 m vertically above its launch point. What are the (a) horizontal
and (b) vertical components of the initial velocity v of the projectile? (c) At the instant the
projectile achieves its maximum height above ground level, how far is it displaced horizontally
from the launch point?


Homework Equations





The Attempt at a Solution



I am working on part a). I was able to determine the horizontal component; however, I am unable to ascertain the vertical component of velocity. I tried applying kinematic equations, but with no avail. I tried to employ a symmetry argument, by finding the velocity acquired as the projectile falls to earth from a vertical distance of 53 m, but then I realized that I don't know the velocity at this point, nor can I suppose that the speed is zero, because it isn't.

What should I do?
 

Answers and Replies

  • #2
6,054
390
There is a formula relating initial velocity, uniform acceleration, displacement and time. You know three of these, thus should be able to find out the remaining unknown.
 
  • #3
1,421
5
Are you speaking of this formula: vi = (y -.5at^2)/t. If so, how can I apply it when I need to set t = 0, in order to determine the initial velocity?
 
  • #4
6,054
390
At what value of ##t## do you know ##y##? Why would you let ##t = 0## instead?
 
  • #5
1,421
5
I figured that I would set t = 0, because that is the instant whose velocity I am trying to find.
 
  • #6
6,054
390
At ## t = 0 ##, ## y = 0 ##, so your equation is ## 0 = v_i \cdot 0 - g \cdot 0^2 / 2 ##, which is useless. But you are given data at ## t ## different than 0, so use that.
 

Related Threads on Reviewing Newtonian Mechanics

  • Last Post
Replies
4
Views
5K
  • Last Post
Replies
3
Views
2K
  • Last Post
Replies
2
Views
2K
  • Last Post
Replies
4
Views
1K
  • Last Post
Replies
2
Views
2K
Replies
5
Views
558
  • Last Post
Replies
3
Views
2K
  • Last Post
Replies
1
Views
5K
  • Last Post
Replies
4
Views
4K
  • Last Post
Replies
14
Views
2K
Top