Riding the elevator

  • Thread starter pmelt
  • Start date
  • #1
3
0

Homework Statement


A 48 kg passenger rides in an elevator that starts from rest on the ground floor of a building at t = 0 and rises to the top floor during a 10 s interval. The acceleration of the elevator as a function of the time is shown in Fig. 3-32, where positive values of the acceleration mean that it is directed upward. Give the magnitude and direction of the following forces.

Fig. 3-32 (in words)
-max positive acceleration = 2 m/s^2 at t = 2 s
-max negative acceleration = -3 m/s^2 at t = 8.5 s
-0 acceleration from 4 s to 7 s


(a) the maximum force on the passenger from the floor

(b) the minimum force on the passenger from the floor

(c) the maximum force on the floor from the passenger



Homework Equations


F = ma

The Attempt at a Solution


For part a), I thought it would just be F =(48kg)(2), but that was not correct. I know it's in an upward direction, but I can't seem to find the magnitude.

Part b) I figured that the minimum force should be when the acceleration = 0, so I tried F=(48)(0) = 0. But it just doesn't seem logical to me...

Part c) I think the maximum force should be when a = -3, but I plugged it into the formula and it was not correct.

Any help would be appreciated, thanks!
 

Answers and Replies

  • #2
LowlyPion
Homework Helper
3,090
5

Homework Statement


A 48 kg passenger rides in an elevator that starts from rest on the ground floor of a building at t = 0 and rises to the top floor during a 10 s interval. The acceleration of the elevator as a function of the time is shown in Fig. 3-32, where positive values of the acceleration mean that it is directed upward. Give the magnitude and direction of the following forces.

Fig. 3-32 (in words)
-max positive acceleration = 2 m/s^2 at t = 2 s
-max negative acceleration = -3 m/s^2 at t = 8.5 s
-0 acceleration from 4 s to 7 s


(a) the maximum force on the passenger from the floor

(b) the minimum force on the passenger from the floor

(c) the maximum force on the floor from the passenger



Homework Equations


F = ma

The Attempt at a Solution


For part a), I thought it would just be F =(48kg)(2), but that was not correct. I know it's in an upward direction, but I can't seem to find the magnitude.

Part b) I figured that the minimum force should be when the acceleration = 0, so I tried F=(48)(0) = 0. But it just doesn't seem logical to me...

Part c) I think the maximum force should be when a = -3, but I plugged it into the formula and it was not correct.

Any help would be appreciated, thanks!

Welcome to PF.

What do you figure is the effect of gravity on the passenger?
 
  • #3
3
0
Thanks :)

Since the elevator is accelerating upward for a) and b), would you subtract the acceleration from gravity?
 
  • #4
LowlyPion
Homework Helper
3,090
5
Thanks :)

Since the elevator is accelerating upward for a) and b), would you subtract the acceleration from gravity?

No. You would add the forces. But ... one of the forces is negative because 1 of the accelerations is negative. Accelerating up would add the force. Decelerating (slowing at the top) would subtract.

(Draw from your own experience in an elevator.)
 
  • #5
3
0
Okay I got it now.. so then would a) and c) have the same magnitude because of Newton's 3rd law?

Thank you very much by the way, much appreciated.
 
  • #6
LowlyPion
Homework Helper
3,090
5
Okay I got it now.. so then would a) and c) have the same magnitude because of Newton's 3rd law?

Thank you very much by the way, much appreciated.

Looks like it don't you think?
 

Related Threads on Riding the elevator

Replies
2
Views
2K
  • Last Post
Replies
15
Views
2K
Replies
1
Views
2K
  • Last Post
Replies
1
Views
3K
  • Last Post
Replies
1
Views
1K
  • Last Post
Replies
4
Views
2K
  • Last Post
Replies
1
Views
4K
  • Last Post
Replies
4
Views
2K
  • Last Post
Replies
3
Views
2K
  • Last Post
Replies
9
Views
843
Top