- #1

- 3

- 0

## Homework Statement

A 48 kg passenger rides in an elevator that starts from rest on the ground floor of a building at t = 0 and rises to the top floor during a 10 s interval. The acceleration of the elevator as a function of the time is shown in Fig. 3-32, where positive values of the acceleration mean that it is directed upward. Give the magnitude and direction of the following forces.

**Fig. 3-32 (in words)**

-max positive acceleration = 2 m/s^2 at t = 2 s

-max negative acceleration = -3 m/s^2 at t = 8.5 s

-0 acceleration from 4 s to 7 s

(a) the maximum force on the passenger from the floor

(b) the minimum force on the passenger from the floor

(c) the maximum force on the floor from the passenger

## Homework Equations

F = ma

## The Attempt at a Solution

For part a), I thought it would just be F =(48kg)(2), but that was not correct. I know it's in an upward direction, but I can't seem to find the magnitude.

Part b) I figured that the minimum force should be when the acceleration = 0, so I tried F=(48)(0) = 0. But it just doesn't seem logical to me...

Part c) I think the maximum force should be when a = -3, but I plugged it into the formula and it was not correct.

Any help would be appreciated, thanks!