*SOLVED*Riemann Sum Question *SOLVED* My question is quite simple. I probably just missed something somewhere. I've looked for hours and cannot find the mistake. 1. The problem statement, all variables and given/known data Find the area under the curve using the definition of an integral and Gauss summation equations: f(x) = 3 - (1/2)x where x is greater than or equal to two and less than or equal to 14 2. Relevant equations Formula #1: Gauss equation for the sum of a list simple list of numbers eg 1,2,3,etc.: [n(n+1)]/2 Formula #2: to find area using Riemann sums: lim as n→∞ of Ʃ from i=1 to n of: f[(i*(b-a))/n]*[(b-a)/n] 3. The attempt at a solution Using Formula #2: lim as n→∞ of Ʃ from i=1 to n of: f[12i/n]*(12/n) pulling out 12/n from under the summation sign: lim as n→∞ of 12/n * Ʃ from i=1 to n of: 3 - (6i/n) pulling 36/n out from underneath the summation sign because it has no "counting" i variable: lim as n→∞ of 36/n - (72/n^2) * Ʃ from 1 to n of i Using Formula #1 to get rid of the summation sign: lim as n→∞ of 36/n - (72n^2 + 72n)/2n^2 crossing out the factors n^2 and 2, which are in the N and D of the 2nd fraction: lim as n→∞ of 36/n - 36 - 36/n taking the limit: -36 Now what's the problem? ∫142 3 - (1/2)x dx = -12 What went wrong? Again, I've been checking this thing for hours.