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- Thread starter KataKoniK
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KataKoniK said:

What do you mean??Have you read you question after writing it,to see whether it makes any sense?If the superior Riemann sum is different from the inferior one,the definite integral does not exist.Period.Since they involve taking a limit,that is not multivalued.

Daniel.

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HallsofIvy

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KataKoniK said:

That's not a very well phrased question. If you are given a particular partition, P, and a function, f, the Lf(P) is the sum of "length of interval times least value of f in that interval" and is a specific number. There are not "many different answers". The same is true of Uf(P). In general, Lf(P)< Uf(P).

Of course, a different choice of P might result in different answers.

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nm I got it!

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