# Riemann Sums

mateomy
We're going over the intro stuff to integration and we are being asked to find the value of the sums...

Here's the problem Im getting stuck on....

$$\sum_{i=1}^{n} (i^2 + 3i + 4)$$

I know that I have to separate the individual sums, so I put it into this form....

$$\sum_{i=1}^{n} i^2 + 3\sum_{i=1}^{n} i + \sum_{i=1}^{n} 4$$

And then I know the individual forms of the Riemann sums of i^2 and i, etc.

$$\sum_{i=1}^{n} i^2 = \frac{n(n+1)(2n+1)}{6} etc, etc....$$

am I just adding these together as if they were fractions (finding common denominators, etc)?