Riemann Sums

  • Thread starter mateomy
  • Start date
  • #1
307
0
We're going over the intro stuff to integration and we are being asked to find the value of the sums...

Here's the problem Im getting stuck on....

[tex]
\sum_{i=1}^{n} (i^2 + 3i + 4)
[/tex]

I know that I have to separate the individual sums, so I put it into this form....

[tex]
\sum_{i=1}^{n} i^2 + 3\sum_{i=1}^{n} i + \sum_{i=1}^{n} 4
[/tex]

And then I know the individual forms of the Riemann sums of i^2 and i, etc.

[tex]
\sum_{i=1}^{n} i^2 = \frac{n(n+1)(2n+1)}{6} etc, etc....
[/tex]

am I just adding these together as if they were fractions (finding common denominators, etc)?
 

Answers and Replies

  • #2
22,089
3,297
Yes, you could just put them together like fractions.
 
  • #3
307
0
Awesome, thanks.
 

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