1. The problem statement, all variables and given/known data A rifle shoots a 4.20 g bullet out of its barrel. The bullet has a muzzle velocity of 955 m/s just as it leaves the barrel. Assuming a constant horizontal acceleration over a distance of 43.0 cm starting from rest, with no friction between the bullet and the barrel, what force does the rifle exert on the bullet while it is in the barrel? 2. Relevant equations f=ma Vx^2=Vox+2ax(x-xo) 3. The attempt at a solution I did (955)^2/ 2*.43m to get the acceleration of 1029.8m/s^2 when i do F=ma I get 4.3218 which the online homework is saying is incorrect.