A rifle is aimed horizontally at the center of a large target 200 m away. The initial speed of the bullet is 500 m/s. Where does the bullet strike the target? To hit the center of the target, the barrel must be at an angle above the line of sight. Find the angle of elecation of the barrel. So far I know that in the x-direction: V0 = 500 m/s x= 200 m in the y-direction: V0= 0 m/2 a = 9.81 m/s^2 and I know that they have time in common. But I don't really know where to go from here. Do we even have enough information to solve the problem?