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## Main Question or Discussion Point

Hey everyone, I was wondering if someone could help me understand what exactly is happening with a certain integral I am working with, which is as follows:

∫2/(u^2-1)du

My steps are as follows (I used partial fractions):

∫(1/(u-1) - 1/(u+1))du = ∫1/(u-1)du - ∫1/(u+1) = ln[(u-1)/(u+1)]

However, here is where my issue arrises; when checking my answer with Mathematica, if I input the very first line above I get:

ln[(1-u)/(1+u)]

Could someone help me understand if it is my method that is flawed or maybe the way I am inputting it into the program when I check my answer. Any assistance is greatly appreciated, thanks!

∫2/(u^2-1)du

My steps are as follows (I used partial fractions):

∫(1/(u-1) - 1/(u+1))du = ∫1/(u-1)du - ∫1/(u+1) = ln[(u-1)/(u+1)]

However, here is where my issue arrises; when checking my answer with Mathematica, if I input the very first line above I get:

ln[(1-u)/(1+u)]

Could someone help me understand if it is my method that is flawed or maybe the way I am inputting it into the program when I check my answer. Any assistance is greatly appreciated, thanks!