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a sign weighing 400 N is suspended at the end of a uniform rod 4.00 m weighing 500 N. what is the tension in the support cable if it makes an angle 40 with the rod?

now i'm curious i don't think Tclockwise = Tcounterclockwise comes into play

so i thought of this as a typical static equilibrium problem, but there is only 1 unknown that is the T in the cable that needs to be broken up into a vector

so exactly how does this get setup then

sum of Fx = Cos40F1 = 500 N + 500 N?

sum of Fy = Sin40F1 = 500 N + 400 N?

i know i am missing something