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**1. Homework Statement**

a rod with mass 'M' and length 'L' is pivoted about a frictionless axle through it's end .a bullet with mass 'm' and speed 'v' is shot and sticks to the rod a distance 'a' from the axle.

I need to find the LINEAR momentum of the system just after the hit.

**2. Homework Equations**

moment of inertia of a rod about it's center of mass: I=(1/12)*M*L^2

L = I*(omega)

p = (m+M)*V

**3. The Attempt at a Solution**

the intial angular momentum is: mva (about the pivot)

angular momentum after the hit is just: I*omega

where I = (1\3)*M*L^2 + m*(a^2)

equating those two gives omega,by the relation V=omega*L

we can get the speed V,so P = (m+M)*V

and this is not the answer

thanks for the help

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