1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Rigid Body: bullet and a rod

  1. Jan 17, 2007 #1
    1. The problem statement, all variables and given/known data

    a rod with mass 'M' and length 'L' is pivoted about a frictionless axle through it's end .a bullet with mass 'm' and speed 'v' is shot and sticks to the rod a distance 'a' from the axle.

    I need to find the LINEAR momentum of the system just after the hit.

    2. Relevant equations

    moment of inertia of a rod about it's center of mass: I=(1/12)*M*L^2
    L = I*(omega)
    p = (m+M)*V

    3. The attempt at a solution

    the intial angular momentum is: mva (about the pivot)
    angular momentum after the hit is just: I*omega
    where I = (1\3)*M*L^2 + m*(a^2)

    equating those two gives omega,by the relation V=omega*L
    we can get the speed V,so P = (m+M)*V

    and this is not the answer

    thanks for the help
    Last edited: Jan 17, 2007
  2. jcsd
  3. Jan 17, 2007 #2


    User Avatar
    Science Advisor
    Homework Helper

    The velocity you calculated is not the velocity you need. Your equation for P should give you a hint about the velocity you do need.
  4. Jan 17, 2007 #3
    I really don't see,how the equation for P should give me a hint,can you be more specific?

    can you tell me what is the velocity I calculated?
  5. Jan 18, 2007 #4


    User Avatar
    Science Advisor
    Homework Helper

    You calculated the velocity of the end of the rod. The only thing moving with that velocity is the tiny bit of mass at that end. Everything else is moving slower.

    The linear momentum of a system of particles is the sum of the linear momenta of each bit of mass in the system. The concept of the center of mass is important because you can find this total momentum by finding the velocity of the center of mass and treating all the mass as if it had that same velocity [P = (m+M)*V_cm]
  6. Jan 18, 2007 #5
    I tried to work in the center of mass frame,(although it's messy),but how can I find V_cm?..should I just compute angular momentum before the hit and after the hit,in the CM frame,and equate them?

    thanks for your help
  7. Jan 18, 2007 #6


    User Avatar
    Science Advisor
    Homework Helper

    Your initial idea for finding the angular velocity of the system after the collision is correct. Once you have found ω you have two ways to approach the solution. You can either find the center of mass of the whole system and use the distance from the pivot to the CM with ω to find the velocity, or you can find the linear momentum of the bullet using its distance from the pivot (a), ω, and m, and combine that with the linear momentum of the CM of the rod to get the total linear momentum of the system.
  8. Jan 19, 2007 #7
    thank you very much..(I finally got it..spent like 3 hours on this)

    thanks again :)
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?

Similar Discussions: Rigid Body: bullet and a rod
  1. Rigid body (Replies: 1)

  2. Rigid Rod (Replies: 3)

  3. Rigid bodies (Replies: 5)

  4. Rigid rod (Replies: 3)