hi, i'll be glad to get some help with that.(adsbygoogle = window.adsbygoogle || []).push({});

thanks

A thin uniform rod has mass M = 0.5 kg and length L= 0.55 m. It has a pivot at one end and is at rest on a compressed spring as shown in (A) in the attached image. The rod is released from an angle θ1= 63.0o, and moves through its horizontal position at (B) and up to (C) where it stops with θ2 = 105.0o, and then falls back down. Friction at the pivot is negligible. Calculate the speed of the CM at (B).

The spring in (A) has a length of 0.11 m and at (B) a length of 0.14 m. Calculate the spring constant k.

I will combine that two mandatory fields as i dont understand the first of them.

In general i see that the first question is an energy conservation question.

i can use the second and third state to find the speed.

so i write an equation where the potential energy of state c equals the kinetic energy of state b, in case i choose the zero line to where the rod is parallel to the ground.

what i don't know is how to treat the potential energy. i know that the kinetic one

consists of the c.m part and the 0.5Iw^2 part but what about mgh, different parts of the rod are in different hights?

thanks

and sorry if i wasn't totally formal, i just didn't know how to

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# Homework Help: Rigid body energy and spring

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