(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Uniform disc, mass m, falls from position where theta 60 degrees. (P is a fixed point on rim of disc).

Calculate the components of thrust along and perpendicular to GP on the smooth hinge at P when theta = 30degrees.

see attatched image for diagram

2. Relevant equations

3. The attempt at a solution

NB: theta with a dot is velocity (v), and theta with two dots is acceleration (r). Not sure if these are actually what the two of them mean, but thats what they'll be represented by.

Transverse Equation:

-ma(r)= mg sin theta - x

x = mgsin theta + ma(r) (1)

Radial Equation

ma (v)^2= y - mgcos theta

Y = ma (v)^2+ mgcos theta (2)

Rotational equation about P

I r= sum of moments

2/3 m(a)^2 r= -mgasin theta

2/3a r= -g sin theta

a r= -(3/2) g sin theta (3)

Integrating (3) gives

a r= -3/2g cos theta + c

c = 3/2g cos theta

at theta = 60

c = 3/2g cos 60

therefore

c = 3/4 g

so

a (v)^2= -3/2g cos theta + 3/4 g

at theta = 30, (3) gives

a r= -3/2g sin30

= -3/4g

(4) gives

a (v)^2= -3/2g cos30 + 3/4g

= -3/2 * root(3)/2g + 3/4g

= -3root(3)/4g + 3/4g

= (3-3root(3))/4 g

From (3), at theta = 60

-ma r= mgsin theta - x

-m(-g/3) = mgsin60 - x

1/3mg = root(3)/2mg - x

1/3mg = root(3)/2mg - x

2/6mg = 3root(3)/6mg - x

x = 3root(3) - 2/6 mg

which is wrong. So I won't even bother looking at my value for y...

And i'm not sure where i've went wrong :/ seems every time i attempt this question I get a different answer.

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Rigid Body Problem

Can you offer guidance or do you also need help?

**Physics Forums | Science Articles, Homework Help, Discussion**