1. The problem statement, all variables and given/known data Given the following diagram If the crate produces a force of gravity of 491 N from the center of gravity G, determine the normal force on both of the wheels and the magnitude and direction of the minimum force required at the grip B needed to lift the load. 2. Relevant equations Fx = 0; Fy= 0; MB = 0; 3. The attempt at a solution Sign Convention: Up and to the right is positive and counter clockwise is positive. from Fx = 0 0= 2Ax - FBcos(theta) (equation 1) from Fy = 0 0= FBsin(theta) - 491N + 2Ay (equation 2) from MB = 0 0 = -2Axcos60(0.1) +2 Aysin60(0.1) - (491cos30)(0.6) (equation 3) from 1 Ax= 0.5FBcos(theta) (1A) from 2 Ay = 0.5(491N-FBsin(theta) (2A) Substitute 1A and 2A into 3 After Simplifying I have -0.05FBcos(theta)-0.0866FBsin(theta) =212.61 I am now stuck as to how to proceed. I am wondering if my initial free body diagram is flawed. Does the wheel at A produce a horizontal force Ax and a Vertical force Ay? Or is Ay the only force produced. The problem with my equations is I seem to have to many unknowns.