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Rigid Objects in equilibirum

  1. Mar 12, 2009 #1
    A 1200 N uniform beam is attached to a vertical wall at one end and is supported by a cable at the other end. A W = 1960 N crate hangs from the far end of the beam.

    Picture: http://edugen.wiley.com/edugen/courses/crs1507/art/qb/qu/c09/ch09p_20.gif

    Calculate the magnitude of the tension in the wire.


    So I know that sum of forces and torques equals 0. Using the hinge as the axis of rotation:

    Torque from crate = -1960Lcos(30)
    Torque from beam = -1200(L/2)cos(30)
    What would the torque from the tension in the wire be? It's directed 50 degrees above the horizontal so I thought it would be T*Lcos(50) but that is wrong. Can someone point me in the right direction? Thanks.
     
    Last edited: Mar 12, 2009
  2. jcsd
  3. Mar 13, 2009 #2

    rl.bhat

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    It's directed 50 degrees above the horizontal so I thought it would be T*Lcos(50) but that is wrong.
    To find the torque from the tension find the horizontal component of the T and find its vertical distance from the hinge. The product will give you the required torque.
     
  4. Mar 13, 2009 #3
    Sorry I'm not quite sure what you mean. In the solution it divided the sum of the torques from the crate and the beam by cos(10). Where did they get that from?
     
  5. Mar 13, 2009 #4

    rl.bhat

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    Torque due to the tension is Tcos50*Lsin30
     
  6. Mar 14, 2009 #5
    no that's not right. the answer is 2251N. Using your torque for the wire gives an answer of 6898.
     
  7. Mar 14, 2009 #6

    Doc Al

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    What's the angle between the wire and the beam? Use that angle to determine the torque.
     
  8. Mar 14, 2009 #7
    Well I'm guessing it's cos(10) but I don't know where that is coming from.
     
  9. Mar 14, 2009 #8

    Doc Al

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    Why guess? You have the diagram. Figure out the angle.
     
  10. Mar 14, 2009 #9
    That's what they had in the solution. From the pic I'm getting an angle of 30 between the wire and beam.
     
  11. Mar 14, 2009 #10

    Doc Al

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    We'll get to the solution soon enough. First find the angle.

    How do you get that? The diagram states that the wire is 50 degrees from the horizontal, so its angle with the beam must be even greater.
     
  12. Mar 14, 2009 #11
    It would be 80 yes?
     
  13. Mar 14, 2009 #12

    Doc Al

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    Yes! Now how do you use that to calculate torque?
     
  14. Mar 14, 2009 #13
    oh okay. so it's T*Lsin80 since force has to be perpendicular to the lever arm.
     
  15. Mar 14, 2009 #14

    Doc Al

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    Good! And to relate it to your solution, sin80 = cos ?
     
  16. Mar 14, 2009 #15
    =cos10. Thank you very much. Much appreciated.
     
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