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**A 1200 N uniform beam is attached to a vertical wall at one end and is supported by a cable at the other end. A W = 1960 N crate hangs from the far end of the beam.**

Picture: http://edugen.wiley.com/edugen/courses/crs1507/art/qb/qu/c09/ch09p_20.gif

Calculate the magnitude of the tension in the wire.

Picture: http://edugen.wiley.com/edugen/courses/crs1507/art/qb/qu/c09/ch09p_20.gif

Calculate the magnitude of the tension in the wire.

So I know that sum of forces and torques equals 0. Using the hinge as the axis of rotation:

Torque from crate = -1960Lcos(30)

Torque from beam = -1200(L/2)cos(30)

What would the torque from the tension in the wire be? It's directed 50 degrees above the horizontal so I thought it would be T*Lcos(50) but that is wrong. Can someone point me in the right direction? Thanks.

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