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Rigidly rotating relativistic string

  1. May 15, 2005 #1
    I am reading Zwiebach's 'a first course in string theory' and I have a question. As an example of a solution to the equations of motion he uses a rigidly rotating string with length l in the x-y plane with it's center at the origin. I would like to do some calculations using as parameters

    [tex]\tau=t[/tex] and [tex]\sigma =s[/tex]

    with s the distance from the origin, and t just time. s runs from -l/2 to l/2. This should be possible right, as I'm free to choose wich way to paramterize the string.

    Now the solution is (given that the string lies along the x-axis at t=0) ofcourse:

    [tex] \vec{X} (t,s) = s(cos(\omega t), sin(\omega t))[/tex]

    As the endpoints are not tied down to anything I have to use free enpoint conditions wich means the endpoints move at the speed of light. This yields for the enpoints [tex]c= \omega l/2[/tex]. Futhermore you can calculate that l is related to the energy of the string E by:

    [tex]\frac{2}{\pi} \frac{E}{T_0}[/tex]

    With T0 the tension of the string. Now the solution is complete as both l and omega are found.

    Now I would like to calculate the angular momentum, so I can find [itex]\alpha '[/tex] the constant of proprtianality between the angular momentum and the energy squared (in terms of hbar). I tried:

    [tex]J= \int _{-l/2} ^{l/2} X_1 P_2 - X_2 P_1 ds [/tex] should be [tex]\frac{E^2}{2 \pi T_0 x}[/tex]

    but now I don't know what expression to use for P the momentum density. I tried:

    [tex]\vec{P} =\frac{T_0}{c^2} \frac{\partial \vec{X}}{\partial t}[/tex]

    but this yields a result a factor 4/3pi off. So I guess there is something wrong with my expression for P. [itex]T_0/c^2[/itex] is the rest mass density of a relativistic string. But my string is moving, so I tried

    [tex]\vec{P}=\gamma (v) \frac{T_0}{c^2} \frac{\partial \vec{X}}{\partial t}[/tex]

    with [itex]v= \omega s[/itex], but this diverges bacause gamma explodes at the string endpoints. What's wrong? How to calculate the angular momentum using [itex] \sigma =s[/itex]?
  2. jcsd
  3. May 2, 2010 #2
    would be nice to have an answer to this question....I would be very interested to see how alpha prime is derived.
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