# Rindler Observer

1. Apr 13, 2011

### pythagoras88

Hi,

I read sean carroll book, "spacetime and geometry" and in the last chapter where he tries to derive unruh effect, he introduced the concept of Rindler coordinate.

There is this part where he considers an accelerating observer in minkowski metric and introduce the trajectory blah blah. My question is, since the observer is accelerating, there must be some sort of fuel or energy propelling, so this energy by itself will actually result in curvature in the spacetime manifold. So isn't the consideration of accelerating observer in minkowski space invalid??

Thanks in advance for any response.

2. Apr 13, 2011

### Bill_K

The observer is supposed to be a 'test particle,' i.e. one who's mass is small enough that its own gravitational field is negligible.

3. Apr 13, 2011

### pythagoras88

oh, ok.... haha... i guess it is a trivial question. So it is juest an accelerating particle that does not affect the spacetime.

Initially i was thinking, because an accelerating observer will have an rindler horizon given by x=t and x=-t. Then is it possible that the energy used to accelerate the particle cause a curvature in spacetime such that it create an event horizon. Then maybe this event horizon may actually coincide with the rindler horizon.