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Rising water level

  1. Dec 8, 2011 #1
    1. The problem statement, all variables and given/known data

    Suppose that a zone of low atmospheric pressure (a "low") is at some place on the surface of the sea. The pressure at the center of the "low" is 64 mm-Hg less than the pressure at a large distance from the center. By how much will this cause the water level to rise at the center?



    2. Relevant equations
    p-p0= -p(density)gy



    3. The attempt at a solution

    First I converted 64 mm-Hg to Pa using 1.01X10^5 Pa/760 mm-Hg and I got 8505.27 Pa

    p-p0=-p(density)gy
    101325 Pa-8505.27 Pa=1000X9.8Xh
    h=92819.73/9800=9.47 m

    According to the book, the answer is 0.85 m
     
  2. jcsd
  3. Dec 8, 2011 #2

    gneill

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    Staff: Mentor

    The pressure value that you've been given is already a pressure difference, so there's no need to invoke atmospheric pressure. All you need is the height of a column of water (seawater, which has a slightly different density than pure water!) that will produce that pressure at its base.
     
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