1. The problem statement, all variables and given/known data [PLAIN]http://img14.imageshack.us/img14/4355/screenshot20110807at249.png [Broken] 2. Relevant equations v(t) = Vmax * e^(-Rt/L) i(t) = imax * e^(-Rt/L) P = V^2/R w = integral of power w/ respect to time w(0) = .5Li^2(0) = energy stored in inductor 3. The attempt at a solution Well for #3, for the estimates of I and R, all I did was put the v(t) = Vmax*e^(-Rt/L) in my calculator w/ Vmax as 60 and L as 40mH. I played around with different R values and found that if I put R =1, the graph in my calculator is identical to the one as above. To solve for I (current source), I used V = IR => I = 60 Amps. For #4, I just used the energy equation w(0) = .5Li^2(0) = .5*40e^-3 * 60^2 = 72 Joules For #5, I integrated the power w/ respect to time to get the energy. But first I needed to solve for the power equation. P = V^2(t)/R where v(t) = -60e^(-t/40e^-3) and R = 1. So then the energy equation was then the integral of 3600e^(-50t) dt from 0 to .02 milli seconds, which equals .716412 Joules. The percentage = .07164/72 * 100 = .1% I don't feel good about these answers and not sure if I did them right. Any help would be greatly appreciated. Thank you.