Suppose there is a circuit consisting of a battery, a resistor, and an inductor, and that there is initially no current. As current is increasing, the inductor creates an induced current in the opposite direction. I am confused as to which end of the inductor is at a higher voltage. Since the induced current is in the opposite direction as the natural current, shouldn't the natural current enter the inductor through the lower voltage end? I know this is not true because this would mean that there is an increase in voltage which would completely change the differential equation using Kirchoff. Why is the end of the inductor that the current first enters the higher voltage end?