Finding Current Through Inductor via Kirchoff's Method

In summary, the current through the inductor is .500 A at t = 0s, but increases to 1.50 A by t = infinite.
  • #1
Gear300
1,213
9
Circuit is shown in attachement. At t = 0s, switch S is closed. Find a function for the current through the inductor starting from t = 0s.

Using Kirchoff's method, I find that the maximum current through the inductor is .500 A as t approaches infinite and that the total current is 1.50 A. I took in the assumption that from t = 0s and onward, the current through the path with the inductor is proportionally 1/3 of the total current. Then I set up an equation:

E - 3IR1 - IR2 - L*dI/dt = 0, in which E is the emf of the battery, I is the current through the inductor, R1 is the resistor on the top left (4.00 Ohm), R2 is the resistor on the top right (8.00 Ohm), L is the inductance, and dI/dt is a derivative of the current. R1 carries the total current, so its current would be 3 times the current in R2. Using this equation, I set up a differential equation, receiving:
I = .500*(1 - e^(-20t)), in which the maximum current corresponds to the maximum current I got from Kirchoff's method.
However, the answer I'm supposed to get is I = .500*(1 - e^(-10t))...I didn't see anything wrong in my method. Any help?
 

Attachments

  • Circuit.jpg
    Circuit.jpg
    11.6 KB · Views: 392
Last edited:
Physics news on Phys.org
  • #2
Any help...
 
  • #3
Gear300 said:
Circuit is shown in attachement. At t = 0s, switch S is closed. Find a function for the current through the inductor starting from t = 0s.

Using Kirchoff's method, I find that the maximum current through the inductor is .500 A as t approaches infinite and that the total current is 1.50 A. I took in the assumption that from t = 0s and onward, the current through the path with the inductor is proportionally 1/3 of the total current.

That's not true. The current through the inductor directly after closing the switch is 0, but the total current is not 0.
 
  • #4
So then how would I model a situation like this? I keep bumping into answers that differ from the one I'm supposed to get.
 
  • #5
you use Kirchhofs laws like in a resistor network, and use L*(dI/dt) for the potential difference across the inductor
 
  • #6
...Isn't that sort of what I did?
 
  • #7
Hi Gear300,

Since the current through the inductor is not one third the current through the battery at all times , you'll need to write down your three equations from Kirchoff's rule again, keeping i1, i2, and i3 as unknowns. (Your differential equation had the current through the inductor explicitly as one third the current through the battery.)

Then use two of the equations to eliminate all currents except the current through the inductor. At that point you'll have a differential equation you can solve.

It looks like you've done most of this process; just with the wrong currents.
 
  • #8
I see. Thanks, so steady-state conditions don't hold at each point in time...alright.
 
  • #9
Wait a minute...I sort of ran into a problem here. Each time I come up with a differential equation, I end up with 2 variable currents. I can eliminate the one I don't need by replacing it with values from equations I get through the Kirchoff's method, but I end up dealing with a 0; the integration still isn't the answer I need...heh, looks like I got into another loop...any help?
 
  • #10
Actually...nevermind that last statement...I just realized that replacing values from Kirchoff's method wouldn't hold valid.
 
  • #11
Nevermind...I have at last realized my mistakes...problem solved.
 

1. How do you use Kirchoff's method to find the current through an inductor?

Kirchoff's method involves applying Kirchoff's Voltage Law (KVL) and Kirchoff's Current Law (KCL) to a closed circuit. By applying these laws, you can create a system of equations that can be solved to find the current through the inductor.

2. What is Kirchoff's Voltage Law?

Kirchoff's Voltage Law states that the sum of all voltages in a closed loop must equal zero. This means that the voltage drops across all components in the circuit must equal the voltage source. This law is used to analyze series circuits.

3. What is Kirchoff's Current Law?

Kirchoff's Current Law states that the sum of all currents entering and leaving a node (or junction) in a circuit must equal zero. This means that the current entering a junction must be equal to the current leaving the junction. This law is used to analyze parallel circuits.

4. Can Kirchoff's method be used to find current through any type of circuit element?

Yes, Kirchoff's method can be used to find current through any type of circuit element, including resistors, capacitors, and inductors. It can also be used to analyze complex circuits with multiple elements.

5. What is the difference between KVL and KCL?

KVL is used to analyze series circuits, where the components are connected in a single loop. KCL is used to analyze parallel circuits, where the components are connected in multiple branches. Both laws are essential for using Kirchoff's method to find current through an inductor.

Similar threads

  • Introductory Physics Homework Help
Replies
6
Views
227
  • Introductory Physics Homework Help
Replies
5
Views
933
  • Introductory Physics Homework Help
Replies
16
Views
2K
  • Introductory Physics Homework Help
Replies
34
Views
5K
  • Introductory Physics Homework Help
Replies
9
Views
2K
  • Introductory Physics Homework Help
Replies
4
Views
687
  • Introductory Physics Homework Help
Replies
19
Views
2K
  • Introductory Physics Homework Help
Replies
18
Views
1K
Replies
25
Views
950
  • Introductory Physics Homework Help
Replies
12
Views
1K
Back
Top