1. The problem statement, all variables and given/known data There is a Battery connected to a single loop circuit containing two resistors, R1 and R2, and one capacitor L. After a long time, the battery is removed, so there is a single loop circuit with just two resistors and a capacitor. What is the current going through R1? 3. The attempt at a solution This is what I thought: So, the EMF is removed. Thus, using a loop rule, we have the formula: 0 = IR + L(di/dt) where R is R1+R2 Integrating, we have 0 = (1/2)(I^2)(R) + (L)(I) Dividing everything by I, we have 0 = (1/2)(I)(R) + L Thus, I = (2L) / R However, this is incorrect. Any ideas? Thanks! 1. The problem statement, all variables and given/known data 2. Relevant equations 3. The attempt at a solution
There are a few problems here. You call this an RL circuit, and you use the equations for an RL circuit, but you say it contains a capacitor instead of an inductor. I assume you are just using the wrong word. The second problem is here: Are you sure you did that correctly? What variable are you integrating with respect to?
You might want to rethink the whole strategy of trying to take an integral or a derivative. You have both I and dI/dt in this equation. What kind of equation does that make it?